8. Calculate the pressure at 5 m depth in water. ($\rho_{water} = 1000\,\text{kg/m}^3$, $g = 9.8\,\text{N/kg}$) [2]
9. Calculate the pressure at 20 m depth in seawater. ($\rho = 1025\,\text{kg/m}^3$, $g = 9.8\,\text{N/kg}$) [2]
Mark Scheme
1. Pressure is force per unit area [1]; $p = F/A$ [1]; $p$ in pascals (Pa), $F$ in newtons (N), $A$ in m² [1] [3]
2. A sharp blade has a smaller contact area [1]; for the same force, smaller area gives greater pressure, which cuts more effectively [1] [2]
3. Fluid particles move randomly in all directions [1]; they collide with surfaces from all angles, exerting the same pressure in all directions at the same depth [1] [2]
4. $p = F/A = 300/0.6 = 500\,\text{Pa}$ [2]
5. $A = F/p = 500/2500 = 0.2\,\text{m}^2$ [2]
6. $A = 0.3 \times 0.2 = 0.06\,\text{m}^2$ [1]; $p = F/A = 12/0.06 = 200\,\text{Pa}$ [2] [3]
7. $p = h\rho g$ [1]; $h$ = depth (m), $\rho$ = density of fluid (kg/m³), $g$ = gravitational field strength (N/kg) [1] [2]
8. $p = h\rho g = 5 \times 1000 \times 9.8 = 49\,000\,\text{Pa}$ (49 kPa) [2]
9. $p = 20 \times 1025 \times 9.8 = 200\,900\,\text{Pa}$ (≈ 201 kPa) [2]
10. Pressure increases with depth ($p = h\rho g$) [1]; so the water exerts greater pressure lower down, requiring a thicker wall to withstand it [1] [2]