3. Calculate pressure at 5 m depth in water ($\rho = 1000\,kg/m^3$, $g = 9.8\,N/kg$). [3]
Mark Scheme
1. Pressure from particle collisions acts equally in all directions [2]
2. $p = F/A = 300/0.6 = 500\,Pa$ [2]
3. $p = h\rho g = 5 \times 1000 \times 9.8 = 49{,}000\,Pa$ [3]