5. A bike travels at $5\,m/s$ and accelerates at $1.0\,m/s^2$ for 8 s. Calculate the distance traveled. [3]
Mark Scheme
1. $a = (13 - 3)/5 = 2\,m/s^2$ [2]
2. $v^2 = 2as = 2 \times 2 \times 20 = 80$; $v \approx 8.9\,m/s$ [3]
3. $a = (v^2 - u^2)/2s = (4^2 - 12^2)/32 = -4\,m/s^2$ [3]
4. $v = at = 1.5 \times 6 = 9\,m/s$; $s = \tfrac{1}{2}at^2 = 0.5 \times 1.5 \times 36 = 27\,m$ [4]
5. $s = ut + \tfrac{1}{2}at^2 = 5 \times 8 + 0.5 \times 1 \times 64 = 72\,m$ [3]